Monday, November 16, 2009

c# detect excel install location in registry and open file

public void OpenInExcel(string filename)
string dir = "";
RegistryKey key = Registry.LocalMachine;
RegistryKey excelKey = key.OpenSubKey(@"SOFTWARE\MicroSoft\Office");
if (excelKey != null)
foreach (string valuename in excelKey.GetSubKeyNames())
int version = 9;
double currentVersion=0;
if (Double.TryParse(valuename, out currentVersion) && currentVersion >= version)
RegistryKey rootdir = excelKey.OpenSubKey(currentVersion + @".0\Excel\InstallRoot");
if (rootdir != null)
dir = rootdir.GetValue(rootdir.GetValueNames()[0]).ToString();
if (dir != "")
ProcessStartInfo startInfo = new ProcessStartInfo();

startInfo.FileName = dir + @"Excel.exe";
startInfo.Arguments = "\"" + fileName + "\"";
startInfo.UseShellExecute = false;

using (Process process = new Process())
process.StartInfo = startInfo;
catch (Exception ex)
Console.WriteLine("\n\nCould not start Excel process.");
MessageBox.Show("Can't Open in excel because excel is not installed.");


Anonymous said...


On Windows x64 the code might fail.

In that case also check the keys below SOFTWARE\Wow6432Node\MicroSoft\Office

Ovi said...

It works on x64 as well. Apparently excelKey.GetSubKeyNames() returns from both SOFTWARE\MicroSoft\Office and SOFTWARE\Wow6432Node\MicroSoft\Office

My problem was parsing the version as a double.
Since the computer culture considers , as decimal separator and . as thousands separator, I changed the if to:
if (Double.TryParse(valuename, System.Globalization.NumberStyles.Any, System.Globalization.CultureInfo.InvariantCulture, out currentVersion) && currentVersion >= version)

Hollis said...


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